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-0.35x^2+210x-3000=0
a = -0.35; b = 210; c = -3000;
Δ = b2-4ac
Δ = 2102-4·(-0.35)·(-3000)
Δ = 39900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{39900}=\sqrt{100*399}=\sqrt{100}*\sqrt{399}=10\sqrt{399}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(210)-10\sqrt{399}}{2*-0.35}=\frac{-210-10\sqrt{399}}{-0.7} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(210)+10\sqrt{399}}{2*-0.35}=\frac{-210+10\sqrt{399}}{-0.7} $
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